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Why not 2 ? Three bits match for interface 2 as well.
I Agree !
Thanks. Can you share any resource that discusses the same ?
Whats the approach ? Do you solve by taking statements as example or some other way ?
I do not think CSL can be RE, it can only be recursive. As the tape for LBA is bounded, it is not possible for TM to not halt.
Infact all languages are recursive. Regular, CFLs, CSLs
Thanks !! My bad. Pretty straight forward question. Got wound up in finding memory blocks, etc.
Using the memory address and extracting the block number outta it was the only thing to be done !
Sir...need your help for calculus :)
Sampling RTTs are based on exponential average.
NewRTT = (1-Smoothening Factor)*OldRTT + Smoothening Factor*ActualRTT
Therefore, 0.5*10 + 0.5*20 =15ms