Pritam is the co-founder of OpenSense Labs and an alumnus of IIT Kharagpur. He qualified GATE-13 with percentile 99.93 . He also possess more than 3 years of industry experience of working for services based companies like TCS, AZRI Solutions & Enova Technologies.

### Alma Mater:

M. Tech.
IIT Kharagpur
2013 to 2015
B. E.
University Institute of Technology, RGPV, Bhopal
2007 to 2011

### Experience:

Director
Perfecist Technologies
2015
Application Developer
Azri Solutions
2012 to 2013
Tata Consultancy Services (TCS)
2011 to 2012
Web Developer
E-nova Technologies, Okhla, New Delhi
2009 to 2010
Tech
Post
5 months 3 weeks ago

Storage classes (Auto, Static, Extern and Register) and its memory, scope, life, default initial value and linking.

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Varun Singla
Niket Gangwar
vaishali
Prashant Sharma
shailaja Praharaju
Gourav Jain
RAHUL TIWARI
sardendu
Prof R.K. Dhawan
LAVESH RAWAL
ARUN SINGH
Vaishali
shivani

## Pages

Tajinder Singh Minhas
3
Ranita Biswas
906
atchyut kumar
908
Ankur Jain
913
Rajeev
914
Vivek Vikram Singh
921
Priyesh Priyatam
923
Himanshi
976
Shreyans Dhankhar
977
Ribhu Ranjan
986
PANKAJ NAYAK
989
vasudha
990
Mahesh Kumar
1017
Chandan Chawda
1019
Parul Agarwal
1044

## Pages

12 Dec 2017 - 7:18pm

It will remain same.

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29 Aug 2017 - 8:35pm

You need to mark a topic as completed in the status section after completion.

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19 Aug 2017 - 9:32pm

Let us apply the recursion-tree method for solving this recurrence problem:

The cost of the root is n because it is the combined cost to divide and merge back the results from the conquered subprocesses. Now here you can see that the height of the subtrees will be largest for T(n-1). It is equivalent to the fact mentioned by @arpitdhuriya that T(n-1) is asymptotically larger.

Hence the complexity would be O(n2)
More precisely, Ω(n2)

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Why don't you give it a try and we correct.

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Yes, None of the options is correct.

We can apply a bottom up approach (as you said) for better understanding:

1. SELECT P.pid FROM Parts P WHERE P.color<> 'blue' : Non-Blue parts id
2. SELECT C.sid FROM Catalog C WHERE C.pid NOT IN (1):  Supplier ID who supply at least one blue part
3. SELECT S.sname FROM Suppliers S WHERE S.sid NOT IN (2): Supplier name who supplies only non-blue parts.

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This is a simple one.

when you draw an  n x n matrix like below:

So, you have (1+ 2 + 3 + 4 + .... n-1 + n = ) n(n+1)/2 places where you have elements present. How the size depends on the data type being stored in the array.

Hence size = n(n+1)/2 * sizeof(data_type)

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11 Aug 2017 - 11:22am

Well Done!

That's how one should always approach to the problem. Remember, getting the solution is not our goal. Our aim should be to develop the problem-solving ability.

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10 Aug 2017 - 2:55pm

Why don't you give it a try, I will help you to reach to the answer.

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9 Aug 2017 - 12:45pm

Answer would be d) b & c

I want you to give it a try with the following hint:

1. For broadcast, host ids will be all 1
2. Assuming that the host bit N would be the host bit try to find the possible IPs

I suggest you to solve it by your own.

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8 Aug 2017 - 11:01pm

Techtud test series are found at http://virtualgate.in

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