About

Pritam is the co-founder of OpenSense Labs and an alumnus of IIT Kharagpur. He qualified GATE-13 with percentile 99.93 . He also possess more than 3 years of industry experience of working for services based companies like TCS, AZRI Solutions & Enova Technologies.

Role

Alma Mater:

M. Tech.
IIT Kharagpur
2013 to 2015
B. E.
University Institute of Technology, RGPV, Bhopal
2007 to 2011

Experience:

Director
Perfecist Technologies
2015
Application Developer
Azri Solutions
2012 to 2013
Business Analyst
Tata Consultancy Services (TCS)
2011 to 2012
Web Developer
E-nova Technologies, Okhla, New Delhi
2009 to 2010
Tech
Post
1 month 2 weeks ago
Most often freshers mention the difficulty they face when they join the industry after completing the graduation. For some of them, it becomes the real challenge to adapt to the new environment where your capability is not judged just by looking at a single piece of paper, but by many factors like your problem-solving skills, team management, on-time delivery, quick learning skills and many other significant factors.

I believe, Internship is one of the ways where you get an opportunity to have a close understanding of how differently companies operate and what is the most suitable career path for you.

Do not miss an internship this summer!!

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Please prefer to type rather than uploading image.

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22 Jun 2016 - 11:39am

What you can see above is the solution.

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Considering VY as primary key, any combination of attributes will be a super key containing VY.

Now you can find the answer. Right ?

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12 Jun 2016 - 11:06pm

As I understand, you want a SQL example of above RA expression:

Set student info who has joined institute after 2015 and are studying Computer Science;

SQL: SELECT * FROM (SELECT * FROM Student WHERE subject='Computer Science') WHERE Join_date > 2015;

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12 Jun 2016 - 9:07am

In Rigorous 2PL all locks are released only after commit; hence, it is quite easy to implement.

But, at the same time Rigorous 2PL may hamper the concurrency, However, it has been practically noticed that it doesn't make any performance difference.

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11 Jun 2016 - 8:58pm

Hradesh, This is a great catch. Your answer is more precise and correct.

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Yes, that will be a good idea.

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I believe the easiest way to solve such problems are to take some values of n and do a comparative analysis.

Following is the order I am able to get:

\(2^\sqrt{2logn} < (\sqrt{2} )^ {logn} < n^2 < (logn)! < e^n < n!\)

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11 Jun 2016 - 4:07pm

Important: On an average, to serve each request, head has to move half the number of tracks and  half the rotation.

So, time taken to do the above work = 250 ms (for half tracks) + (1/600)*(60)*(1/2)*1000 ms (for half rotation)

= 300 ms

Now, calculate the time needed to read 250 bytes.
= (250/500)*(1/100)*(1/10)*1000
= 0.5 ms

Hence, total time = 300.5 ms

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