About

Pritam is the co-founder of OpenSense Labs and an alumnus of IIT Kharagpur. He qualified GATE-13 with percentile 99.93 . He also possess more than 3 years of industry experience of working for services based companies like TCS, AZRI Solutions & Enova Technologies.

Role

Alma Mater:

M. Tech.
IIT Kharagpur
2013 to 2015
B. E.
University Institute of Technology, RGPV, Bhopal
2007 to 2011

Experience:

Director
Perfecist Technologies
2015
Application Developer
Azri Solutions
2012 to 2013
Business Analyst
Tata Consultancy Services (TCS)
2011 to 2012
Web Developer
E-nova Technologies, Okhla, New Delhi
2009 to 2010
Tech
Post
1 month 2 weeks ago
Most often freshers mention the difficulty they face when they join the industry after completing the graduation. For some of them, it becomes the real challenge to adapt to the new environment where your capability is not judged just by looking at a single piece of paper, but by many factors like your problem-solving skills, team management, on-time delivery, quick learning skills and many other significant factors.

I believe, Internship is one of the ways where you get an opportunity to have a close understanding of how differently companies operate and what is the most suitable career path for you.

Do not miss an internship this summer!!

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Base should be same for both LHS and RHS while solving.

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What is the test and question number ?

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10 Sep 2016 - 11:48pm

Choose any option, calculate time to travel 528 KM with that speed. increase speed by 5.5 km/h, calculate the time again. See if the time difference is 4/3 hours. If yes, that's your answer. If no, choose next option to check upon smartly.

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10 Sep 2016 - 11:28pm

A quich way would be to check from options.

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2 is the number of children. Hence, the number of keys = number of children-1

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Here branching factor or capacity = 6

So, non-root can have minimum of \(\left \lceil \frac{6}{2} \right \rceil -1\)=  2  children [which is leaf in this case]

Hence, minimum number of key/s that a non-root can have = 2-1 =1  [for leaf node]

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If the question "Can I do it or not?"  Then Yes.

One can take entire UOD in a single table and consider set of all attribute as key, but then the whole intention of DBMS is lost. We as a DBMS student have to see that we are not compromising any principle.

For instance, consider the following example:

Employee(Eid, Name, DBO)  Mobile(Eid, Number)

But if we take one single table Emp_mobile(Eid, Name, DBO, Number), It means we are saying that Eid Number →Name. Here, we have lost a dependency Eid →Name, which is never desirable.

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20 Aug 2016 - 2:42pm

I think, asking whether a schedule is 2PL serialisable would be wrong. One can ask, if 2PL ensures serializibility or not, and the answer would be YES in this case.

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20 Aug 2016 - 12:56pm

The question is not quite clear to me. Do you want to ask that what is the locking protocol which can ensure serialisability ?

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