I am too Lazy to update about me.

Not updated.

### Experience:

Not updated.
Tud
2 years 1 month ago

This case comes under Undifined Behavior.See this https://en.wikipedia.org/wiki/Undefined_behavior .

moreless
Tud
2 years 4 months ago

Because here it is not transitive.ie. If A > B ,B > C then its not necessary that A > C.How I found it is not transitive?.The question has a hint!.

Tud
2 years 4 months ago
Tud
2 years 5 months ago

Here they did't consider the long jump also they explicitly mentioned that it should not be consider in calculation.And here they consider the long jump.In Galvin also the long jump is considered.Also provide a better reference or explanation .Arul

Tud
2 years 5 months ago

D.

Pratip Sarkar
Ravindra Babu Ravula
Himanshu Kaushik
Arul
Anurag Verma
Piyush Balwani
Dhrupit Dave
Arvind Rawat
Arjun Suresh
M Manohar
Shreyans Dhankhar
Vivek Vikram Singh
atchyut kumar
Pritam Prasun
Parimal Andhalkar
2408
Abhishikt Venkata
13157
YASH
13725
Rohit Soneta
13843
shreeja
31295
krishn kumar gupta
42915
29 May 2016 - 3:19pm

This case comes under Undifined Behavior.See this https://en.wikipedia.org/wiki/Undefined_behavior .

more less
19 Feb 2016 - 11:39am

Here they did't consider the long jump also they explicitly mentioned that it should not be consider in calculation.And here they consider the long jump.In Galvin also the long jump is considered.Also provide a better reference or explanation .Arul

more less
16 Feb 2016 - 11:25pm

Are you sure about this.Because in some text books also consider the long jumps in to calculation but some foreign universities don't.

more less

No.of non diagnol elements is n^2 - n.So pair 2 of them(a[i][j] and a[j][i]).So it will be  (n^2 - n)/2.

more less

For symmetric matrices A=A^T ,so :A[i][j]==A[j][i].And so if they are paired up there will be (n^2 - n)/2 pairs.And the pairs can be 0 or 1.So 2^(n^2 - n)/2.And for diagonal elements can be 0 or 1.So 2^n.Total will be (2^(n^2 - n)/2 )*  (2^n) which is C.

P.S:n^2 is total elements in a n*n matrix and n will be no. of diagonal elements.

more less
2 Feb 2016 - 11:18pm

it will be 24^4.Check ur formula.

more less
29 Jan 2016 - 12:13pm

YES.

more less
22 Jan 2016 - 5:49pm

Go through the Distributive property.Answer will be B.

more less
17 Jan 2016 - 8:17pm

The question says "Without any additional circuitry " and "An 8 *1 mux can be used " so answer should be C.  Because to implement 4 variable function in 8*1 MUX we need additional circuitry ie.MUX.

Note:MUX is functionally Complete,so any function(NOT,AND,...) can be implemented using a MUX.

more less
17 Jan 2016 - 8:16pm

The question says "Without any additional circuitry " and "An 8 *1 mux can be used " so answer should be C.  Because to implement 4 variable function in 8*1 MUX we need additional circuitry ie.MUX.

Note:MUX is functionaly Complete,so any function(NOT,AND,...) can be implemented using a MUX.

more less